(c^2-3c+4)(3c-2)=

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Solution for (c^2-3c+4)(3c-2)= equation: 


Simplifying
(c2 + -3c + 4)(3c + -2) = 0

Reorder the terms:
(4 + -3c + c2)(3c + -2) = 0

Reorder the terms:
(4 + -3c + c2)(-2 + 3c) = 0

Multiply (4 + -3c + c2) * (-2 + 3c)
(4(-2 + 3c) + -3c * (-2 + 3c) + c2(-2 + 3c)) = 0
((-2 * 4 + 3c * 4) + -3c * (-2 + 3c) + c2(-2 + 3c)) = 0
((-8 + 12c) + -3c * (-2 + 3c) + c2(-2 + 3c)) = 0
(-8 + 12c + (-2 * -3c + 3c * -3c) + c2(-2 + 3c)) = 0
(-8 + 12c + (6c + -9c2) + c2(-2 + 3c)) = 0
(-8 + 12c + 6c + -9c2 + (-2 * c2 + 3c * c2)) = 0
(-8 + 12c + 6c + -9c2 + (-2c2 + 3c3)) = 0

Combine like terms: 12c + 6c = 18c
(-8 + 18c + -9c2 + -2c2 + 3c3) = 0

Combine like terms: -9c2 + -2c2 = -11c2
(-8 + 18c + -11c2 + 3c3) = 0

Solving
-8 + 18c + -11c2 + 3c3 = 0

Solving for variable 'c'.

The solution to this equation could not be determined.

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